Suppose you are given two strings s and t. String t is generated by random shuffling string s and then adding one more letter at a random position. Return, the letter that was added to t.
Example 1: Input: s = “abcd”, t = “ceadb-
Output: “e” Explanation: “cadb” was produced by random shuffling “abcd” and “e” was added in as the second letter.
Example 2: Input: s = “abbdd”, t = “dabadb” Output: “a”
Example3: Input: s = “”, t = “y” Output: “y” Example4: Input: s = “aaaa”, t = “aabaa-Output: “b”:
Example 5: Input: s = “ae”, t = “aae” Output: “a” using C#
Here’s a possible C# implementation of the function:
csharpCopy codepublic static char FindAddedLetter(string s, string t)
{
int[] letterCounts = new int[26];
foreach (char c in s)
{
letterCounts[c - 'a']++;
}
foreach (char c in t)
{
letterCounts[c - 'a']--;
}
for (int i = 0; i < 26; i++)
{
if (letterCounts[i] < 0)
{
return (char)('a' + i);
}
}
return '\0'; // no letter was added
}
The function takes in two parameters s
and t
, representing the original string and the shuffled string with one added letter. It first initializes an array letterCounts
to keep track of the count of each letter in s
. It iterates over each character in s
, incrementing the count of the corresponding letter in the letterCounts
array.
The function then iterates over each character in t
, decrementing the count of the corresponding letter in the letterCounts
array. The letter that was added to t
will have a count of -1 in the letterCounts
array.
Finally, the function iterates over the letterCounts
array and returns the letter that was added to t
. If no letter was added, the function returns the null character ‘\0’.
You can call this function like this:
javaCopy codestring s = "abcd";
string t = "ceadb";
char addedLetter = FindAddedLetter(s, t);
Console.WriteLine(addedLetter);
This will output e
, which is the expected result for the given input.